2022-01-06 11:50发布
考研数学张宇18讲中一道例题求解释
考研数学张宇18讲中一道例题求解释 ^^^^当1/2<=x<2>x^(2n)，且(2x)^n>1所以专[(2x)^n]^(1/n)<=原式<=[3*(2x)^n]^(1/n)2x<=原式<=2x*3^(1/n)同理属，当2<=x时，x^(2n)>(2x)^n，且x^(2n)>1所以[x^(2n)]^(1/n)<=原式<=[3*x^(2n)]^(1/n)x^<=原式<=x^2*3^(1/n)
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考研数学张宇18讲中一道例题求解释 ^^^^当1/2<=x<2>x^(2n)，且(2x)^n>1所以专[(2x)^n]^(1/n)<=原式<=[3*(2x)^n]^(1/n)2x<=原式<=2x*3^(1/n)同理属，当2<=x时，x^(2n)>(2x)^n，且x^(2n)>1所以[x^(2n)]^(1/n)<=原式<=[3*x^(2n)]^(1/n)x^<=原式<=x^2*3^(1/n)
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